4^5x-9=(1/27)^2x-8

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Solution for 4^5x-9=(1/27)^2x-8 equation: 



4^5x-9=(1/27)^2x-8

We move all terms to the left:

4^5x-9-((1/27)^2x-8)=0



Domain of the equation: 27)^2x-8)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

4^5x-((+1/27)^2x-8)-9=0

We multiply all the terms by the denominator


4^5x*27)^2x-8)-((-9*27)^2x-8)+1=0

We add all the numbers together, and all the variables

4^5x*27)^2x-8)-((-243)^2x-8)+1=0

Wy multiply elements

108x^6-243)^2x-8)+1=0

We do not support expression: x^6

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